Hi. jermstur.
I'm still a amateur, too.:yh:
If you use 5 of 1N5405 and 0.2ohm at 1.2A like this:
flexdrive(+)--1N5404--1N5404--1N5404--1N5404--1N5404--0.2ohm--flexdrive(-)
1. the minimum wattage of resistor should be 0.288W.
[ P = I * V = I * (I * R) = 1.2 * 1.2 * 0.2 = 0.288 W ]
2. total voltage drop
= Vdrop of 1N5404 + Vdrop of reistor[ V = I * R ]
= 0.8 * 5 + 1.2 * 0.2
= 4.24V
3. the current of your test load should be 5 times of the voltage measured at your DMM.
V = I * R = I * 0.2
I = 5 * V
It is difficult to simulate exact Vdrop because there is some variation between laser diodes, and Vdrop of 1Nxxxx is 0.7-0.9V fixed step, not a spectrum.
I tested with 1ohm. It's simple V=I.
And remember one thing. At near 1A, 5-pin chip of flexdrive should be heatsinked.
I wish this may help your 445nm build.
Good luck.
SHIN
I'm still a amateur, too.:yh:
If you use 5 of 1N5405 and 0.2ohm at 1.2A like this:
flexdrive(+)--1N5404--1N5404--1N5404--1N5404--1N5404--0.2ohm--flexdrive(-)
1. the minimum wattage of resistor should be 0.288W.
[ P = I * V = I * (I * R) = 1.2 * 1.2 * 0.2 = 0.288 W ]
2. total voltage drop
= Vdrop of 1N5404 + Vdrop of reistor[ V = I * R ]
= 0.8 * 5 + 1.2 * 0.2
= 4.24V
3. the current of your test load should be 5 times of the voltage measured at your DMM.
V = I * R = I * 0.2
I = 5 * V
It is difficult to simulate exact Vdrop because there is some variation between laser diodes, and Vdrop of 1Nxxxx is 0.7-0.9V fixed step, not a spectrum.
I tested with 1ohm. It's simple V=I.
And remember one thing. At near 1A, 5-pin chip of flexdrive should be heatsinked.
I wish this may help your 445nm build.
Good luck.
SHIN