Recent content by c0hereNT

Oh, sorry, i expected good implementation so i didnt check the computing part. Where you have x:=x/2*a; and x2:=x2/2*a; you should have x:=x/(2*a); and x2:=x2/(2*a); Regards.

Interesting, with the 'z' i thought, that you could only write Readln; Sorry for stupid question, but have you tried entering negative "c" or "b"? I still think its because of sqrt from negative number. I tried it with many numbers and i worked. Try for example a=6; b=-15; c=6 and you should...

This works great for me. As nikokapo said, you were getting negative (or too small) numbers under the sqrt. At the end you have to write some number because 'z' is integer. Or what problem at the end do you mean? Before you start to calculate, you should do something like if Sqr(b) < (-4*a*c)...

Thanks Glenn, i can't wait, haha :drool: Regards.

Hi, Gleen. Thanks! You are the best :bowdown: If you had time, could you please measure mine yellow pen's power and write it here or by PM? Thanks.

Hi, i'm sorry if it was mentioned, but couldn't find it. How much would GLP-593.5 2mW be? And has it got an IR filter? I'm not sure if in DL they don't glue it into it. Thank you very much.